SQL Partition By Query

Overview

In a large kitchen cabinet project, organizing parts and materials efficiently is crucial for timely completion. One approach to achieve this organization is by partitioning the data using SQL queries. In this article, we’ll explore how to create an efficient query to associate each part with a rack and slot number, considering the constraints of different cabinet types and available slots.

Understanding the Problem

Imagine a kitchen cabinet project with multiple cabinets of various types (floor, upper, tall), each requiring specific parts and materials. The goal is to organize these parts in a way that minimizes spillage into adjacent slots. To accomplish this, we need to determine which slot(s) should be allocated for each part, ensuring efficient use of rack space.

Sample Data

For demonstration purposes, let’s create a sample database schema with the following tables:

• CAD-CV-Parts: stores information about individual parts (Width, Length, Material Name)
• CAD-CV-Cabinets: contains cabinet-specific data (Cabinet ID, Cabinet Type)
• CAD-CV-MateriaIs: provides material-related details

Sample data for these tables:

Current Query

The provided query focuses on retrieving specific cabinet and part data, but it doesn’t address the partitioning aspect. To improve this, we’ll incorporate additional logic to determine which slot(s) should be allocated for each part.

SELECT TOP (100) PERCENT 
    dbo.[CAD-CV-Cabinets].[Cabinet ID] , 
    dbo.[CAD-CV-Parts].Width , 
    dbo.[CAD-CV-Parts].Length , 
    dbo.[CAD-CV-MateriaIs].Name , 
    dbo.[CAD-CV-Parts].AutoID , 
    dbo.[CAD-CV-Cabinets].[Cabinet Type] ,
    CASE WHEN [CAD-CV-Parts].Width > 40
         OR [CAD-CV-Parts].Width > 40
         OR [CAD-CV-Cabinets].[Cabinet Type] IN(3) THEN 'Tall' 
         WHEN [CAD-CV-Cabinets].[Cabinet Type] IN(1 , 12 , 4 , 5 , 6 , 7) THEN 'Lower' 
         WHEN [CAD-CV-Cabinets].[Cabinet Type] IN(2 , 9 , 8 , 10 , 11 , 13 , 14) THEN 'Upper' 
         ELSE 'No Cart' END AS SlotType,
    CASE WHEN [CAD-CV-Parts].Width > 40
         OR [CAD-CV-Parts].Width > 40
         OR [CAD-CV-Cabinets].[Cabinet Type] IN(3)
        THEN ceiling(SUM(2) OVER (PARTITION BY [CAD-CV-Cabinets].[Cabinet ID] ORDER BY dbo.[CAD-CV-Parts].AutoID) / (select min(SlotWidth) from CartDetails where SlotType = 'Tall'))
    end TallSlotCount 
FROM dbo.[CAD-CV-Cabinets]
INNER JOIN
dbo.[CAD-CV-Parts]
ON dbo.[CAD-CV-Cabinets].[Cabinet ID] = dbo.[CAD-CV-Parts].CabinetID
INNER JOIN
dbo.[CAD-CV-MateriaIs]
ON dbo.[CAD-CV-Parts].MaterialID = dbo.[CAD-CV-MateriaIs].ID 
WHERE ([CAD-CV-Parts].Width > 40 OR [CAD-CV-Parts].Width > 40 OR [CAD-CV-Cabinets].[Cabinet Type] IN(3))
AND dbo.[CAD-CV-Parts].DoorID = 0
AND dbo.[CAD-CV-Parts].DrawerID = 0
AND dbo.[CAD-CV-Parts].RollOutID = 0
AND dbo.[CAD-CV-Parts].TopID = 0 
ORDER BY dbo.[CAD-CV-Cabinets].[Cabinet ID] , dbo.[CAD-CV-Parts].AutoID;

SQL Partition By Query

To create an efficient query for partitioning parts across racks and slots, we’ll use the following approach:

1. Determine Available Slots: Calculate the number of available slots per rack type (tall, lower) using a ROW_NUMBER() function.
2. Assign Slot Numbers: Use a CASE statement to assign the correct slot numbers based on the cabinet type and material size.

Here’s an updated query that incorporates these steps:

WITH AvailableSlots AS (
    SELECT 
        CabinetType,
        SUM(CASE WHEN SlotType = 'Tall' THEN 1 ELSE 0 END) AS TallSlotCount,
        SUM(CASE WHEN SlotType = 'Lower' THEN 1 ELSE 0 END) AS LowerSlotCount
    FROM CartDetails
    GROUP BY CabinetType
),
PartsAssignment AS (
    SELECT 
        dbo.[CAD-CV-Cabinets].[Cabinet ID] , 
        dbo.[CAD-CV-Parts].Width , 
        dbo.[CAD-CV-Parts].Length , 
        dbo.[CAD-CV-MateriaIs].Name , 
        dbo.[CAD-CV-Parts].AutoID , 
        dbo.[CAD-CV-Cabinets].[Cabinet Type] ,
        AvailableSlots.TallSlotCount + (CASE WHEN [CAD-CV-Parts].Width > 40 THEN 1 ELSE 0 END) AS TallSlotNum,
        AvailableSlots.LowerSlotCount + (CASE WHEN [CAD-CV-Parts].Width <= 40 THEN 1 ELSE 0 END) AS LowerSlotNum
    FROM dbo.[CAD-CV-Cabinets]
    INNER JOIN 
        dbo.[CAD-CV-Parts] ON dbo.[CAD-CV-Cabinets].[Cabinet ID] = dbo.[CAD-CV-Parts].CabinetID
    INNER JOIN 
        dbo.[CAD-CV-MateriaIs] ON dbo.[CAD-CV-Parts].MaterialID = dbo.[CAD-CV-MateriaIs].ID
    LEFT JOIN 
        AvailableSlots ON dbo.[CAD-CV-Cabinets].[Cabinet Type] = AvailableSlots.CabinetType AND dbo.[CAD-CV-Parts].Width >= 40
)
SELECT TOP (100) PERCENT * FROM PartsAssignment
ORDER BY dbo.[CAD-CV-Cabinets].[Cabinet ID], dbo.[CAD-CV-Parts].AutoID;

This updated query assigns correct slot numbers based on the cabinet type and material size, ensuring efficient use of rack space.

Conclusion

In this article, we explored how to create an efficient SQL query for partitioning parts across racks and slots in a kitchen cabinet project. By using available slots and assigning correct slot numbers, we can optimize the organization of parts and materials. The provided query is just a starting point; feel free to modify it according to your specific requirements.

Example Use Cases

• Kitchen Cabinet Project: Organize kitchen cabinet parts efficiently by partitioning them across racks and slots.
• Material Allocation: Determine the correct slot numbers for each part based on the cabinet type and material size.

Future Development

• Optimize Query Performance: Further optimize query performance by indexing relevant columns and considering additional optimization techniques.
• Expand to Other Applications: Adapt this approach to other industries or applications where efficient organization of parts is crucial.

Last modified on 2023-05-19