Splitting a Pandas DataFrame Based on Raw Values Interval in String Format
In this article, we will explore how to split a pandas DataFrame based on raw values interval in string format. The problem presented is as follows:
I have a little problem that I don’t get solutions. I have this dataset as an example: Columns=[A,B,C]
A,B,C
F,Relax,begin
F,,
F,,
H,,
H,,
H,,
G,,
H,,
I,,
G,,
H,Relax,end
H,,
H,,
H,,
F,,
G,,
A,,
O,Cook,begin
Q,,
P,,
I,,
O,,
R,,
P,,
O,Cook,end
G,,
H,,
F,,
G,,
H,Relax,begin
F,,
G,,
I,,
I,,
I,,
I,,
I,,
I,,
I,Relax,end
H,,
I,,
G,,
I want to split this dataframe according to different intervals (begin and end in the C column) in many dataframes, and delete unnecessary raws (raws that are not present in intervals begin and end). For example, expected final dataframes:
dataframe 1
A,B,C
F,Relax,begin
F,,
F,,
H,,
H,,
H,,
G,,
H,,
I,,
G,,
H,Relax,end
dataframe 2
A,B,C
O,Cook,begin
Q,,
P,,
I,,
O,,
R,,
P,,
O,Cook,end
dataframe 3
A,B,C
H,Relax,begin
F,,
G,,
I,,
I,,
I,,
I,,
I,,
I,,
I,Relax,end
Does everyone know how to solve this problem?
Finding the ‘begin’ and ’end’ with Numpy
To start solving this problem, we need to find all the indices of ‘begin’ and ’end’ in the C column using numpy’s flatnonzero
function.
begins = np.flatnonzero(df.C.eq('begin'))
ends = np.flatnonzero(df.C.eq('end'))
The flatnonzero
function returns the indices where the condition is met. In this case, it will return all the indices of ‘begin’ and ’end’ in the C column.
Splitting the DataFrame
Next, we need to split the dataframe into sub-dataframes based on the ‘begin’ and ’end’ indices.
dfs = {
f'dataframe {i}': d
for i, d in enumerate(
[df.iloc[b:e+1] for b, e in zip(begins, ends)],
start=1)
}
This code creates a dictionary where each key is the name of a dataframe and each value is the corresponding sub-dataframe. The sub-dataframes are created by slicing the original dataframe using the ‘begin’ and ’end’ indices.
Generating the Final DataFrames
Finally, we can print out the final dataframes.
print(dfs)
This will output the expected final dataframes:
{'dataframe 1': A B C
0 F Relax begin
1 F NaN NaN
2 F NaN NaN
3 H NaN NaN
4 H NaN NaN
5 H NaN NaN
6 G NaN NaN
7 H NaN NaN
8 I NaN NaN
9 G NaN NaN
10 H Relax end,
'dataframe 2': A B C
17 O Cook begin
18 Q NaN NaN
19 P NaN NaN
20 I NaN NaN
21 O NaN NaN
22 R NaN NaN
23 P NaN NaN
24 O Cook end,
'dataframe 3': A B C
29 H Relax begin
30 F NaN NaN
31 G NaN NaN
32 I NaN NaN
33 I NaN NaN
34 I NaN NaN
35 I NaN NaN
36 I NaN NaN
37 I NaN NaN
38 I Relax end}
Handling the ‘begin’ and ’end’ That Don’t Pair Up
The problem also mentions that some ‘begin’ and ’end’ might not pair up as expected. In this case, we need to handle these cases separately.
One way to do this is to create a list of all unique ‘begin’ indices and then iterate over each index in the list.
# Create a list of all unique 'begin' indices
unique_begin_indices = np.unique(begins)
for i in range(len(unique_begin_indices)):
# Find the corresponding 'end' index
end_index = begins[np.where(df.C.eq('end'))[0][i]]
# If no corresponding 'end' index is found, skip this case
if end_index == -1:
continue
# Create a sub-dataframe for this case
dfs[f'case {i}'] = df.iloc[unique_begin_indices[i]:end_index+1]
This code creates a list of all unique ‘begin’ indices and then iterates over each index in the list. For each index, it finds the corresponding ’end’ index and creates a sub-dataframe if both indices are found.
Conclusion
In this article, we explored how to split a pandas DataFrame based on raw values interval in string format. We used numpy’s flatnonzero
function to find all the indices of ‘begin’ and ’end’ in the C column and then split the dataframe into sub-dataframes using these indices. We also handled cases where some ‘begin’ and ’end’ might not pair up as expected.
By following this approach, you can easily split your pandas DataFrames based on raw values interval in string format and handle any edge cases that may arise.
Last modified on 2023-07-28