Understanding the Problem and the Current Code
The problem at hand involves cleaning and transforming a dataset that contains information about employees, their statuses, and manager IDs. The goal is to create a new table with only active employees who are not managers of other employees.
We have been provided with an example code snippet that attempts to solve this problem but seems to be stuck. In this article, we’ll break down the current code, understand what’s going wrong, and then provide a step-by-step guide on how to achieve our desired output.
Problem Statement
Given a table of employee information, including Emp_ID
, Status
, Manager_ID
, and Employee_count
, we want to filter out employees who are terminated (Termed
) and not managers of other employees. We also want to count the number of non-terminated employees for each manager ID.
Current Code Analysis
The current code snippet attempts to solve the problem by:
- Grouping the data by
Emp_ID
and taking the last row’sStatus
value. - Mapping this new
Status
value back to all rows in the original dataset. - Counting the unique
Emp_ID
s for eachManager_ID
. - Merging these counts with the mapped
Status
values.
However, there are a few issues with the current code:
- The first step assumes that the last row of each
Emp_ID
has the correct status, which might not always be true. - The second step maps the wrong value to all rows in the original dataset (it should map to the
Employee_count
column). - The third and fourth steps are incorrect and do not solve the problem.
Step-by-Step Solution
Let’s break down the solution into smaller, manageable pieces:
1. Clean and Transform the Data
First, we’ll create a new column that indicates whether an employee is active or terminated.
import pandas as pd
# Create a sample dataset (in reality, you'd use your actual data)
data = {
'Emp_ID': [1, 2, 3, 4, 5],
'Status': ['Active', 'Active', 'Termed', 'Termed', 'Termed'],
'Manager_ID': [3, 3, 5, 3, -],
'Employee_count': [0, 0, 3, 0, 1]
}
df = pd.DataFrame(data)
# Add a new column that indicates whether an employee is active or terminated
df['Active'] = df['Status'] == 'Active'
2. Filter Out Terminated Employees
Next, we’ll filter out the rows where Emp_ID
is terminated.
# Filter out employees who are terminated
active_df = df[~df['Emp_ID'].isin(df[df['Status'] == 'Termed']['Emp_ID'])]
3. Create a Lookup Series for Manager IDs
We’ll create a lookup series that maps each Manager_ID
to its corresponding count of non-terminated employees.
# Group by Manager_ID and count the number of non-terminated employees
s_mng_cnt = active_df.groupby('Manager_ID')['Emp_ID'].nunique()
# Merge this new column with our original dataset
active_df['Employee_count'] = s_mng_cnt.map(lambda x: x)
4. Final Result
Finally, we’ll select only the columns that we’re interested in and display the result.
# Select only the desired columns and display the result
final_result = active_df[['Emp_ID', 'Status', 'Manager_ID', 'Employee_count']]
print(final_result)
Putting it All Together
Here is the complete code snippet:
import pandas as pd
data = {
'Emp_ID': [1, 2, 3, 4, 5],
'Status': ['Active', 'Active', 'Termed', 'Termed', 'Termin'],
'Manager_ID': [3, 3, 5, 3, -],
'Employee_count': [0, 0, 3, 0, 1]
}
df = pd.DataFrame(data)
active_df = df[~df['Emp_ID'].isin(df[df['Status'] == 'Termin']['Emp_ID'])]
s_mng_cnt = active_df.groupby('Manager_ID')['Emp_ID'].nunique()
active_df['Employee_count'] = s_mng_cnt.map(lambda x: x)
final_result = active_df[['Emp_ID', 'Status', 'Manager_ID', 'Employee_count']]
print(final_result)
This code snippet should give you the desired output. Remember to replace the sample data with your actual dataset.
Last modified on 2023-09-30