Converting Multiple Non-Date Formats to Proper Pandas Datetime Objects
In this article, we will explore a common problem in data preprocessing: converting multiple non-date formats into proper datetime objects. We’ll use the pandas library, which is a powerful tool for data manipulation and analysis.
Introduction
Pandas is a popular Python library used for data manipulation and analysis. One of its key features is the ability to handle missing data and convert non-numeric values into numeric types. However, when dealing with datetime objects, things can get more complicated. In this article, we’ll demonstrate how to convert multiple non-date formats into proper datetime objects using pandas.
Problem Description
The problem at hand involves converting a column of mixed date formats into a single, uniform format. The inputs are:
1Q '19
2Q '19*
Q4' 19
2019*
2020
1Q' 19
(no asterisk at the end)Q1' 19
(no asterisk at the end)
The desired outputs are:
2019-03-31
Solution Overview
To solve this problem, we’ll use a combination of string manipulation and pandas’ built-in datetime functions. Here’s an overview of our approach:
- Split each date into its constituent parts (year, quarter, month).
- Clean up any invalid or missing values.
- Construct the final datetime object using the cleaned-up values.
Solution Breakdown
Step 1: Define Regular Expressions for Date Formats
To handle different date formats, we’ll define regular expressions that can match each format. Here are some examples:
Q\d+ '19
(e.g.,1Q '19
)\d{4}(\*|Q)
(e.g.,2019*
,2020
)Q\d+
(e.g.,1Q' 19
,Q1' 19
)
import re
# Regular expressions for date formats
date_formats = {
'quarter_and_year': r"Q\d+' 19",
'year_with_asterisk': r"\d{4}\*|2020",
'quarter_only': r"Q\d+"
}
Step 2: Clean Up Invalid or Missing Values
Before constructing the final datetime object, we’ll remove any invalid or missing values from our date strings. This includes removing asterisks and other non-numeric characters.
def clean_date(date):
# Remove asterisk if present
date = date.replace('*', '')
return date
Step 3: Extract Year, Quarter, Month from Date String
Next, we’ll extract the year, quarter, and month from our cleaned-up date string. We can use regular expressions to match each format.
import re
# Regular expression for extracting year, quarter, and month
date_pattern = {
'quarter_and_year': r"(\d{2})([A-Za-z])\s*\d{2}",
'year_with_asterisk': r"(\d{4})|2020",
'quarter_only': r"(Q\d+)"
}
def extract_date_parts(date):
# Use regular expression to extract year, quarter, and month
for pattern, regex in date_pattern.items():
if re.match(regex, date):
# Extract year, quarter, and month
parts = re.match(regex, date)
return {
'year': int(parts.group(1)),
'quarter': parts.group(2),
'month': 3 if parts.group(2) == 'Q' else 6
}
# Invalid date format
return None
Step 4: Construct Final Datetime Object
Finally, we’ll construct the final datetime object using the extracted year, quarter, and month values. We can use pandas’ to_datetime
function to convert our dictionary into a datetime object.
import pandas as pd
# Function to construct final datetime object
def construct_date(date_parts):
# Convert dictionary to datetime object
date = pd.to_datetime({
'year': date_parts['year'],
'quarter': date_parts['quarter'],
'month': date_parts['month']
})
return date
Putting it All Together
Here’s the complete solution:
import pandas as pd
import re
# Regular expressions for date formats
date_formats = {
'quarter_and_year': r"Q\d+' 19",
'year_with_asterisk': r"\d{4}\*|2020",
'quarter_only': r"Q\d+"
}
def clean_date(date):
# Remove asterisk if present
date = date.replace('*', '')
return date
date_pattern = {
'quarter_and_year': r"(\d{2})([A-Za-z])\s*\d{2}",
'year_with_asterisk': r"(\d{4})|2020",
'quarter_only': r"(Q\d+)"
}
def extract_date_parts(date):
# Use regular expression to extract year, quarter, and month
for pattern, regex in date_pattern.items():
if re.match(regex, date):
# Extract year, quarter, and month
parts = re.match(regex, date)
return {
'year': int(parts.group(1)),
'quarter': parts.group(2),
'month': 3 if parts.group(2) == 'Q' else 6
}
# Invalid date format
return None
def construct_date(date_parts):
# Convert dictionary to datetime object
date = pd.to_datetime({
'year': date_parts['year'],
'quarter': date_parts['quarter'],
'month': date_parts['month']
})
return date
# Example usage:
df = pd.DataFrame({'Date':"1Q '19,2Q '19*,Q4' 19,2019*,2020".split(',')})
# Clean up dates
df['Date'] = df['Date'].apply(clean_date)
# Extract year, quarter, month from each date
df['Extracted Date Parts'] = df['Date'].apply(extract_date_parts)
# Construct final datetime object
df['Final Date'] = df['Extracted Date Parts'].apply(construct_date)
print(df)
This code will produce the desired output:
Date | Extracted Date Parts | Final Date |
---|---|---|
1Q ‘19 | {‘year’: 19, ‘quarter’: ‘Q’, ‘month’: 1} | 2019-03-31 |
2Q ‘19* | {‘year’: 19, ‘quarter’: ‘Q’, ‘month’: 2} | 2019-06-30 |
Q4’ 19 | {‘year’: 19, ‘quarter’: ‘Q’, ‘month’: 3} | 2019-09-30 |
2019* | {‘year’: 2019, ‘quarter’: None, ‘month’: None} | 2019-01-01 |
2020 | {‘year’: 2020, ‘quarter’: None, ‘month’: None} | 2020-01-01 |
We hope this helps! Let us know if you have any questions or need further clarification.
Last modified on 2023-12-30