Saving Every Dataframe in a List of Dataframes
Introduction
In this blog post, we’ll explore how to save every dataframe in a list using the write.table
function in R. We’ll start by creating a list of dataframes and then discuss various approaches to saving each dataframe individually.
Creating a List of Dataframes
set.seed(1)
S1 = data.frame(replicate(2,sample(0:130,30,rep=TRUE)))
S2 = data.frame(replicate(2,sample(0:130,34,rep=TRUE)))
S3 = data.frame(replicate(2,sample(0:130,21,rep=TRUE)))
S4 = data.frame(replicate(2,sample(0:130,26,rep=TRUE)))
df_list1 = list(S1 = S1, S2 = S2, S3 = S3, S4 = S4)
set.seed(2)
S1 = data.frame(replicate(2,sample(0:130,30,rep=TRUE)))
S2 = data.frame(replicate(2,sample(0:130,34,rep=TRUE)))
S3 = data.frame(replicate(2,sample(0:130,21,rep=TRUE)))
S4 = data.frame(replicate(2,sample(0:130,26,rep=TRUE)))
df_list2 = list(S1 = S1, S2 = S2, S3 = S3, S4 = S4)
set.seed(3)
S1 = data.frame(replicate(2,sample(0:130,30,rep=TRUE)))
S2 = data.frame(replicate(2,sample(0:130,34,rep=TRUE)))
S3 = data.frame(replicate(2,sample(0:130,21,rep=TRUE)))
S4 = data.frame(replicate(2,sample(0:130,26,rep=TRUE)))
df_list3 = list(S1 = S1, S2 = S2, S3 = S3, S4 = S4)
set.seed(4)
S1 = data.frame(replicate(2,sample(0:130,30,rep=TRUE)))
S2 = data.frame(replicate(2,sample(0:130,34,rep=TRUE)))
S3 = data.frame(replicate(2,sample(0:130,21,rep=TRUE)))
S4 = data.frame(replicate(2,sample(0:130,26,rep=TRUE)))
df_list4 = list(S1 = S1, S2 = S2, S3 = S3, S4 = S4)
df_list = list(df_list1, df_list2, df_list3, df_list4)
names(df_list) = c("AB_df", "BC_df", "DE_df", "FG_df")
In this example, we create four dataframes S1
, S2
, S3
, and S4
using the replicate
function. We then create a list of these dataframes and assign names to each element in the list.
Flattening the List
flatlist <- unlist(df_list, recursive = FALSE)
for (n in names(flatlist)) write.csv(flatlist[[n]], sprintf("%s.csv", n))
The answer provided uses the unlist
function to flatten the list of lists into a single list. This allows us to easily access each dataframe individually using its name.
However, let’s dive deeper into how we can achieve this without using unlist
.
Looping Through the List and Saving Each Dataframe
for (i in 1:length(df_list)) {
df_name <- paste("df_list", names(df_list)[i], sep = "$")
write.table(df_list[[i]], df_name, row.names = FALSE)
}
This approach uses a for
loop to iterate through each element in the list. For each iteration, it creates a character string df_name
by concatenating “df_list” with the current name from the list.
However, we have a problem here: names(df_list)[i]
returns a character, but df_list[[i]]
returns a dataframe. In R, when you use square brackets []
, it doesn’t interpret the variable as a string; instead, it interprets it as an index into the vector.
This is where we run into the issue that prevents us from using names(df_list)[i]
. To solve this problem, we need to use double quotes in our string concatenation.
for (i in 1:length(df_list)) {
df_name <- paste0("df_list", names(df_list)[i], ".csv")
write.table(df_list[[i]], df_name, row.names = FALSE)
}
Note that we also changed sep = "$"
to paste0
for better readability.
Another Approach: Using for
Loop with Brackets
names_of_df <- names(df_list)
for (n in names_of_df) {
write.table(df_list[[n]], paste(n, ".csv", sep = ""), row.names = FALSE)
}
In this example, we first extract the names from the list into a vector called names_of_df
. We then use these names directly when writing to file.
Conclusion
Saving every dataframe in a list can be achieved using several approaches. By understanding how R handles variables and string concatenation, you can create your own efficient solutions to this common problem.
Last modified on 2024-02-17