Understanding Dense Rank and Its Equivalent in Postgres: A Comparative Analysis of Techniques

Understanding Dense Rank and Its Equivalent in Postgres

Dense rank is a window function that assigns a unique rank to each row within a partition of a result set. The rank is assigned based on the order of rows and is used to identify the top-performing items or entities.

Postgresql does not natively support dense rank, but there are ways to achieve similar results using other functions and techniques. In this article, we will explore how to convert Oracle’s dense rank syntax into a Postgres equivalent.

Background on Window Functions

Window functions in Postgres allow you to perform calculations across rows that are related to the current row. They can be used for aggregating data, ranking data, or performing other types of calculations that involve multiple rows.

Postgresql supports several window functions, including:

  • ROW_NUMBER(): Assigns a unique number to each row within a partition.
  • RANK(): Assigns a rank to each row within a partition based on the value in the specified column. If two or more rows have the same value, they are assigned the same rank and the next rank is skipped.
  • DENSE_RANK(): Assigns a unique rank to each row within a partition. If two or more rows have the same value, they are assigned the same rank.

Oracle’s dense rank syntax uses the DENSE_RANK() function with an OVER clause to specify the columns used for ranking.

Converting Oracle’s Dense Rank Syntax into Postgres

In this section, we will explore how to convert Oracle’s dense rank syntax into a Postgres equivalent using different techniques.

Technique 1: Using ROW_NUMBER() and a subquery

One way to achieve a dense rank in Postgresql is by using the ROW_NUMBER() function with a subquery. Here’s an example of how you can use this technique:

-- Create a table
CREATE TABLE table_name (id INT, prop2 VARCHAR(255));

-- Insert some data
INSERT INTO table_name (id, prop2) VALUES (1, 'value3'), (2, 'value4'), (3, 'value5');

-- Use ROW_NUMBER() and a subquery to get the dense rank
SELECT id, row_number() OVER (ORDER BY prop2 DESC) AS prop1 FROM table_name;

In this example, we use ROW_NUMBER() with an OVER clause to assign a unique number to each row within the specified column (prop2). The result is a set of rows with their original values in id, but also with a rank assigned based on the order of rows.

Technique 2: Using RANK() and a subquery

Another way to achieve a dense rank in Postgresql is by using the RANK() function with a subquery. Here’s an example of how you can use this technique:

-- Create a table
CREATE TABLE table_name (id INT, prop2 VARCHAR(255));

-- Insert some data
INSERT INTO table_name (id, prop2) VALUES (1, 'value3'), (2, 'value4'), (3, 'value5');

-- Use RANK() and a subquery to get the dense rank
SELECT id, rank() OVER (ORDER BY prop2 DESC) AS prop1 FROM table_name;

In this example, we use RANK() with an OVER clause to assign a rank to each row within the specified column (prop2). The result is a set of rows with their original values in id, but also with a rank assigned based on the order of rows.

Technique 3: Using FETCH FIRST ROW ONLY

Postgresql’s FETCH FIRST ROW ONLY clause can be used to achieve a dense rank. Here’s an example of how you can use this technique:

-- Create a table
CREATE TABLE table_name (id INT, prop2 VARCHAR(255));

-- Insert some data
INSERT INTO table_name (id, prop2) VALUES (1, 'value3'), (2, 'value4'), (3, 'value5');

-- Use FETCH FIRST ROW ONLY to get the dense rank
SELECT id FROM table_name ORDER BY prop2 DESC FETCH FIRST 1 ROW ONLY;

In this example, we use FETCH FIRST ROW ONLY with an ORDER BY clause to assign a unique row to each partition of the result set. The result is a set of rows with their original values in id, but also with a rank assigned based on the order of rows.

Technique 4: Using ROW_NUMBER() and a CTE

Finally, we can use a Common Table Expression (CTE) along with ROW_NUMBER() to achieve a dense rank. Here’s an example of how you can use this technique:

-- Create a table
CREATE TABLE table_name (id INT, prop2 VARCHAR(255));

-- Insert some data
INSERT INTO table_name (id, prop2) VALUES (1, 'value3'), (2, 'value4'), (3, 'value5');

-- Use ROW_NUMBER() and a CTE to get the dense rank
WITH ranked_rows AS (
  SELECT id, row_number() OVER (ORDER BY prop2 DESC) AS prop1
  FROM table_name
)
SELECT * FROM ranked_rows;

In this example, we use ROW_NUMBER() with an OVER clause within a CTE to assign a unique number to each row within the specified column (prop2). The result is a set of rows with their original values in id, but also with a rank assigned based on the order of rows.

Choosing the Right Technique

When choosing between these techniques, consider the specific requirements of your use case. Here are some factors to consider:

  • Performance: Techniques that rely on subqueries may be slower than those that don’t.
  • Complexity: Techniques that involve more complex logic or joins may be more difficult to implement and maintain.
  • Readability: Techniques that are easier to understand and interpret may be better for your use case.

In conclusion, Postgresql provides several ways to achieve a dense rank. While the native DENSE_RANK() function is not available, we can use other functions like ROW_NUMBER(), RANK(), and FETCH FIRST ROW ONLY to get similar results.

By understanding these techniques and their trade-offs, you can choose the best approach for your specific use case and improve your performance, complexity, and readability.


Last modified on 2024-08-18